Question 1161492
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ v_i\ =\ at\ +\ v_o]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ s_i\ =\ \frac{1}{2}at^2\ +\ v_ot\ +\ s_o]


Presuming a standing start, *[tex \Large v_o\ =\ 0], so solving 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 35\ =\ 3t]


for *[tex \Large t] gives the amount of time it takes the aircraft to attain a speed of 35 m/s with an acceleration of 3 m/s²


Then, knowing the value of *[tex \Large t], the distance traveled in *[tex \Large t] seconds at a constant acceleration of 3 m/s² with an initial velocity of zero and an initial distance of zero is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ s\ =\ 1.5t^2\ +\ 0t\ + 0]


Plug in the value of *[tex \Large t] calculated above and then do the arithmetic.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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