Question 1161462


Graph the equation by finding the {{{x}}} and {{{y }}}intercepts.


{{{-4x + 3y = -12}}}


set {{{y=0}}} to find the {{{x}}} intercept  

and set {{{x=0}}} to find {{{y }}} intercept

{{{x}}}|{{{y}}}
{{{3}}}|{{{0}}}->{{{-4x+3*0=-12}}}->{{{-4x=-12}}}->{{{x=-12/-4}}}->{{{x =3}}}
{{{0}}}|{{{-4}}}->{{{-4*0+3y=-12}}}->{{{3y=-12}}}->{{{y=-4}}}


{{{drawing( 600, 600, -10, 10, -10, 10,
circle(3,0,.12), circle(0,-4,.12), 
 graph( 600, 600, -10, 10, -10, 10, 4x/3-4)) }}}