Question 1161407
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Since you didn't specify a quadratic trinomial, a quadratic binomial in the LHS will do just fine.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ 2\ =\ 0]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ +\ \sqrt{2})(x\ -\ \sqrt{2})\ =\ 0]



Or you could try something like:



*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ -\ x\ +\ \frac{3}{16}\ =\ 0]


which factors to:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ -\ \frac{1}{4})(x\ -\ \frac{3}{4})\ =\ 0]


								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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