Question 1161320

Find the sum of three numbers such that the 3rd number is twice the 2nd, and the 2nd exceeds the 1st number which is 80 by 70. Thank you!
<pre>1st number: 80
As 2nd exceeds 1st by 70, 2nd is: 80 + 70 = 150
3rd is TWICE the 2nd, so 3rd is: 2(150) = 300
Can you now find the SUM of the 3?