Question 1161324
yes, it is C

The first term is {{{8}}}, so {{{a[1] = 8}}}

Each time we want a new term, we add on {{{3}}}.

{{{a[n]=3+3*a[n-1] }}} -> {{{a[n-1] }}} is previous term and {{{a[n] }}} is next term ; we add on {{{3}}} to previous term