Question 1161302
Solution.
Let x = 1st number
Let x+2 = 2nd number
Let x+4 = 3rd number
Condition given
6x+5(x+2)+4(x+4) = 356
Distribute 5 through the parenthesis
6x+5x+10+4(x+4) = 356
Distribute 4 through the parenthesis
6x+5x+10+4x+16 = 356
Collect the like terms
15x+10+16 = 356
Add the numbers
15x+26 = 356
Move constant to the right side of the equation and change its sign
15x = 356-26
Subtract the numbers
15x = 330
Divide both sides of the equation by 15
x = 22
Use substitution
x+2 = 22+2 = 24
Use substitution
x+4 = 22+4 = 26
Three consecutive even integers are 22, 24, and 26.