Question 1161296
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Answer: You are correct. The answer is C) -4, -1, 4, 11, 20


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Work Shown:


Plug in n = 1 to find the first term
{{{a[n] = n^2 - 5}}}


{{{a[1] = 1^2 - 5}}}


{{{a[1] = 1 - 5}}}


{{{a[1] = -4}}} is the first term


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Repeat for n = 2 to get the second term
{{{a[n] = n^2 - 5}}}


{{{a[2] = 2^2 - 5}}}


{{{a[2] = 4 - 5}}}


{{{a[2] = -1}}} is the second term


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Let n = 3 and we get...
{{{a[n] = n^2 - 5}}}


{{{a[3] = 3^2 - 5}}}


{{{a[3] = 9 - 5}}}


{{{a[3] = 4}}} as the third term


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Let n = 4 and we get...
{{{a[n] = n^2 - 5}}}


{{{a[4] = 4^2 - 5}}}


{{{a[4] = 16 - 5}}}


{{{a[4] = 11}}} as the fourth term


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And finally the fifth term is worked out below for n = 5
{{{a[n] = n^2 - 5}}}


{{{a[5] = 5^2 - 5}}}


{{{a[5] = 25 - 5}}}


{{{a[5] = 20}}}


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To summarize, we got the sequence -4, -1, 4, 11, 20, which matches with choice C.
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