Question 1161200


The mean of the list
{{{n}}}, {{{n + 3}}},{{{ n+4}}}, {{{n+5}}}, {{{n+6}}}, {{{n+8}}}, {{{n+10}}}, {{{n + 12}}}, {{{n+15}}} is {{{11}}}. What is the median?


The mean is the {{{average}}} of the numbers.

so, calculate {{{n}}}

{{{(n+n + 3+ n+4+ n+5+ n+6+n+8+ n+10+n + 12+ n+15)/9=11}}}

{{{(9n + 63)/9=11}}}

{{{9n + 63=99}}}

{{{9n =99-63}}}

{{{9n =36}}}

{{{n=4}}}


your list is:

{{{4}}}, {{{7}}}, {{{8}}}, {{{9}}},{{{ 10}}},{{{ 12}}}, {{{14}}}, {{{16}}},{{{19}}}

To find the Median, place the numbers in value order (in this case it is already) and find the middle number. 

{{{4}}}, {{{7}}}, {{{8}}}, {{{9}}},{{{highlight( 10)}}},{{{ 12}}}, {{{14}}}, {{{16}}},{{{19}}}


The middle number is {{{10}}}, so the median is {{{10}}}.