<PRE><B>Question 107704</B>
Let the first number be x.  Then the other number must be x + 3.

10 times the first number is 10x, and 3 times the other number is 3(x + 3) so subtracting gives you:


{{{10x-3(x+3)= 33}}}
{{{10x-3x-9=33}}}
{{{7x-9=33}}}
{{{7x=42}}}
{{{x=6}}}

The smaller number is 6, and the larger is 9.


Check:


{{{10*6-3*9=33}}}
{{{60-27=33}}}  Check

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