Question 1161101
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The smallest of 6 consecutive integers is p, and the greatest is q. What is the value of the average of p and q in terms of p?
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<pre>
If the smallest number is  p,  then the greatest is   q = p+5.   Therefore,


    the value of the average of p and q in terms of p is  {{{(p + (p+5))/2}}} = {{{(2p+5)/2}}} = p + 2.5.     <A>ANSWER</U>



<U>CHECK</U>.  Let p = 1;  then q = 6  and the average of the two numbers is  {{{(1+6)/2}}} = {{{7/2}}} = 3.5 = 1 + 2.5.    ! Correct !
</pre>

Solved.


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The solution and the answer by @josgarithmetic both are &nbsp;&nbsp;W R O N G,


since he calculated &nbsp;&nbsp;TOTALLY &nbsp;DIFFERENT &nbsp;average - not which was requested.


Therefore, &nbsp;IGNORE &nbsp;his post, &nbsp;for your safety.