Question 1161088


{{{x^2-(8/9)x=64/81}}}


{{{x^2-(8/9)x+b^2=64/81+b^2}}}.......to completing the square  you add {{{b^2}}} to both sides

where {{{b=(8/9)/2=4/9}}}


{{{x^2-(8/9)x+(4/9)^2=64/81+(4/9)^2}}}.........you adding {{{(4/9)^2=16/81}}}

{{{(x-4/9)^2=64/81+16/81}}}

{{{(x-4/9)^2=80/81}}}