Question 107647
{{{(y^2-y-6)/(y^2-5y-14)}}}
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{{{(y^2+6y+5)/(y^2-6y-7)}}}
;
Factor everything we can:
{{{((y-3)(y+2))/((y-7)(y+2))}}}
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{{{((y+5)(y+1))/((y-7)(y+1))}}}
:
Canceling simplifies things:
{{{((y-3))/((y-7))}}}
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{{{((y+5))/((y-7))}}}
:
Invert the dividing fraction and multiply:
{{{((y-3))/((y-7))}}} * {{{((y-7))/((y+5))}}} = {{{((y-3))/((y+5))}}}; The (x-7)'s canceled leaving us with this
:
Did this make sense to you?