Question 1161067
A woman is 5 years older than her husband
 w = h + 5
or
 h = w - 5
and 10 times as old as their daughter.
 w = 10d
or divide by 10
 d = .1w
 In 14 years, the sum of their ages will be 100.
(w+14) + (h+14) + (d+14) = 100
w + h + d + 42 = 100
w + h + d = 100 - 42
w + h + d = 58
replace h with (w-5), replace d with .1w
w + (w-5) + .1w = 58
2.1w = 58 + 5
2.1w = 63
w = 63/2.1
w = 30 yrs is the woman's age
then
h = 30 - 5
h = 25 yr is the husband's age
and
d = .1(30)
d = 3 yrs is the daughter's