Question 1161065
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Let x be the daughter's age.
Then the woman's age is 10x. (10 times the daughter's age)
Then the man's age is 10x-5. (the woman is 5 years older than him)<br>
If the sum of their ages 14 years from now will be 100, then the sum of their current ages is 100-3(14) = 100-42 = 58.<br>
So<br>
{{{(x)+(10x)+(10x-5) = 58}}}<br>
Solve using basic algebra....<br>