Question 1161056
A vending machine contains nickels, quarters, and dimes with a total value of $83.75.
.05n + .1d + .25q = 83.75
 There are twice as many dimes as nickels,
d = 2n
or divide by2
n = .5d
 and 50 more quarters than dimes.
q = d+50
:
 How many of each coin are there?
replace n and q in the first equation
.05(.5d) + .1d + .25(d+50) = 83.75
.025d + .1d + .25d + 12.5 = 83.75
.375d = 83.75 - 12.5
..375d = 71.25
d = 71.25/.375
d = 190 dimes
then
n = .5(190)
n = 95 nickels
and
q = 190 + 50
q = 240 quarters
:
:
Check this with you calc
.05(95) + .1(190) + .25(240) = 83.75