Question 1161023
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<pre>

You can award the first student giving him (or her) any two of these 8 prizes;
             you can do it by {{{(8*7)/2}}} = 28 different ways.


Next,        you can award the 2-nd student giving him (or her) any two of remaining 6 prizes;
             you can do it by {{{(6*5)/2}}} = 15 different ways.


Next,        you can award the 3-rd student giving him (or her) any two of remaining 4 prizes;
             you can do it by {{{(4*3)/2}}} = 6 different ways.


Finally,     you can ONLY award the 4-th student giving him (or her) the remaining 2 prizes;
             you can do it by only one way - you just have no any other choice.


So, the <U>ANSWER</U> to the problem's question is THIS PRODUCT 28*15*6 = 2520 ways.
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Solved.