Question 1160938
all the items cost 200 minus 54 = 146.
all of the money is in R$, so 146 means R146.
1 liter of milk costs 5 more than a can of tuna.
1 loaf of bread costs 2 less than a liter of milk.
the housewife purchases 5 liters of milk, 3 loaves of bread, and 6 cans of tuna.
let M equal the cost of a liter of milk.
let T equal the cost of a can of tuna.
let B equal the cost of a loaf of bread.
you get:
5M + 3B + 6T = 146.
a liter of milk costs 5 more than a can of tuna and a loaf of bread costs 2 less than a liter of milk, therefore:
M = T + 5.
B = M - 2.
from the first of these two equations, solve for T to get:
T = M - 5
the two equations become:
T = M - 5
B = M - 2
the equation of 5M + 3B + 6T = 146 becomes:
5M + 3(M-2) + 6(M-5) = 146
simplify to get:
5M + 3M - 6 + 6M - 30 = 146
combine like terms to get:
14M - 36 = 146
add 36 to both sides of the equation to get:
14M = 182
solve for M to get:
M = 182 / 14 = 13
since T = M - 5, then T = 8
since B = M - 2, then B = 11
your original equation is 5M + 3B + 6T = 146.
this becomes 5*13 + 3*11 + 6*8 = 146 which becomes 146 = 146, confirming the solution is correct.
your solution is:
the cost of a liter of milk is R13.
the cost of a loaf of bread is R11.
the cost of a can of tuna is R8.