Question 107666

{{{(x+a)(x^2-ax/x)}}}
 
= {{{(x+a)(x(x-a)/x)}}}.....cancel both {{{x}}} in second term
 
= {{{(x+a)(x-a)}}}.............multiply each term with each term

= {{{x^2 - ax + ax – a^2}}}.....cancel {{{-ax}}} and {{{ax}}}

= {{{x^2 – a^2}}}

answer is {{{a}}}