Question 1160899
sqrt(x-3)^2=+/- (x-3)
sqrt(x+2)^2=+/- (x+2)

But the original fractions are not defined when x=-2 or x=3
So when you cross-multiply, you get (x-3)^2, but it is not defined at x=3.
One has to go back to the original function and look at the domain. 

Remember in completing the square problems, one has +/- results
you can get to x=1/2 if (x-3)=-(x+2)=-x-2
then 2x=1 and x=1/2, but that is allowing, if one will, an x-3 from one side, where 3 is in the domain, and x=-2 from the other side, where -2 is part of the domain, if one will, for the numerator.