Question 1160895
The function f(x)=7x+2/x-3, x≠3, is one-to-one.
 Find an equation for f^-1(x), the inverse function.
:
y = {{{(7x+2)/(x-3)}}}
swap x and y and solve for y
x = {{{(7y+2)/(y-3)}}}
multiply both sides by (y-3), cancels out the left side
x(y-3) = 7y + 2
distribute x
xy - 3x = 7y + 2
add 3x to both sides, subtract 7y from both sides
xy - 7y = 3x + 2
factor out y
y(x-7) = 3x + 2
divide both sides by (x-7)
y = {{{(3x+2)/(x-7)}}} is the inverse function