Question 1160873
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Compound interest formula:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ P\(1\,+\,\frac{r}{n}\)^{nt}]


Where *[tex \Large A] is the amount in the account after *[tex \Large t] years, *[tex \Large P] is the initial principal amount, *[tex \Large r] is the annual interest rate expressed as a decimal, and *[tex \Large n] is the number of compounding periods per year.


You want to find *[tex \Large A] where *[tex \Large P\ =\ 40], *[tex \Large r\ =\ 0.05], *[tex \Large n\ =\ 1], and *[tex \Large t\ =\ 2].


You can do your own arithmetic.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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