Question 1160800
Original square,
x and x for length and width
Perimeter:  4x
Area:  x^2


Increased square,
x+4 and x+8 for length and width
Perimeter:  {{{2(x+4+x+8)=2(2x+12)=4x+48}}}
Area:  {{{(x+4)(x+8)=x^2+12x+32}}}



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If the resulting rectangle has an area of 239.25 square feet
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{{{x^2+12x+32=239.25}}}
Simplify and solve this for x, before finding the value of 4x.