Question 1160695
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So, there are 4 possibilities for the last digit in the 4-th position reading from left to right.

    These possibilities are 0, 3, 6 and 9.


Then there are 10-1 = 9 possibilities for the digit in  the 3-rd position;

                      8 possibilities for the digit in  the 2-nd position;

                      7 possibilities for the digit in  the 1-st position.


In all, there are  4*9*8*7 = 2016 different codes, satisfying imposed conditions.
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