Question 1160677
Graph {{{y=(4/3)x-1}}}

you need two points

{{{x}}}|{{{y}}}

{{{0}}}|{{{-1}}}.....{{{y=(4/3)*0-1=-1}}}
{{{3/4}}}|{{{0}}}.....{{{0=(4/3)x-1}}}->{{{1=(4/3)x}}}->{{{1/(4/3)=x}}}->{{{3/4=x}}}

{{{drawing( 600, 600, -10, 10, -10, 10,
circle(0,-1,.12),circle(3/4,0,.12),locate(0.3,-1,p(0,-1)),locate(3/4,0.8,p(3/4,0)),
 graph( 600, 600, -10, 10, -10, 10, (4/3)x-1)) }}}