<PRE><B>Question 107516</B>

{{{f(x)=(x^2+x+105)/(5x-45)}}} Start with the given function



{{{5x-45=0}}} Set the denominator equal to zero. Remember, dividing by 0 is undefined. So if we find values of x that make the denominator zero, then we must exclude them from the domain.




{{{5x=0+45}}}Add 45 to both sides



{{{5x=45}}} Combine like terms on the right side



{{{x=(45)/(5)}}} Divide both sides by 5 to isolate x




{{{x=9}}} Divide


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Answer:

So our answer is {{{x=9}}} 




Since {{{x=9}}} makes the denominator equal to zero, this means we must exclude {{{x=9}}} from our domain


So our domain is:  *[Tex \LARGE \textrm{\left{x|x\in\mathbb{R} x\neq9\right}}]

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