Question 1160549
Consider the demand equation where x represents the quantity demanded in units of a thousand and p is the unit price in dollars.
p = {{{sqrt(16-x^2)}}}
{{{sqrt(16-x^2)}}} = 3
Square both sides
16-x^2 = 9
-x^2 = 9 - 16
-x^2 = -7
which is
x^2 = 7
x = {{{sqrt(7)}}}
x = 2.6457 thousand ~ 2646 units when unit price is $3