Question 1160528
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The area of a rectangle is the length times the width.  But if the length is 5 inches longer than the width, the length can be represented by *[tex \Large w\ +\ 5].  So the area is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ lw\ =\ (w\,+\,5)w\ =\ 50]


Expand, put the quadratic equation in standard form, and solve for the positive root to get the width.  Add 5 for the length.

								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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