Question 107611
Let "l" be the length and "w" be the width of the rectangle.


So according to the given data, the perimeter = 56 units


So, by data:  l = 7 + 2w and w = w


We know that the perimeter is given by P = 2l + 2w 


So substituting for the values, we get: 


56 = 2(7 + 2w) + 2w 


56 = 14 + 4w + 2w


56 - 14 = 6w


42 = 6w


==> {{{w = 42/6}}} 


==> w = 7 


by back substitution we get: 


l = 7 + 2w


l = 7 + 14 


l = 21


Thus, the solution