Question 1160397
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*[illustration BaseballDiamondRateofChangeCropped.jpg].


The distance to 2nd base as a function of the remaining distance to 1st base is


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ D_{2nd}(x)\ =\ \sqrt{90^2\,-\,x^2}]


Compute the first derivative and evaluate at *[tex \Large x\ =\ 45] which is the value of *[tex \Large x] when the runner is half-way to first base.


Similarly:


The distance to 3rd base as a function of the remaining distance to 1st base is


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ D_{3rd}(x)\ =\ \sqrt{90^2\,-\,(90\,-\,x)^2}]


Compute the first derivative and evaluate at *[tex \Large x\ =\ 45] which is the value of *[tex \Large x] when the runner is half-way to first base.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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