Question 107605
Pick a series of values for x and evaluate to determine the corresponding y.  Plot those points on a graph and draw a smooth curve.


{{{3x^2-x^3}}}

if x = 0, y = 0, so the point (0,0) is on the graph

if x = 1, then y = 2 => (1,2)
if x = -1, then y = 4 => (-1,4)
if x = 2, then y = 12-8 = 4 => (2, 4)
if x = -2, then y = 12+8 = 20 => (-2, 20)
if x = 3, then y = 0 => (3, 0)
if x = -3 then y = 54 => (-3, 54)

Plot as many points as you think you need to define the curve.  It should look something like this:


{{{graph(400,600,-4,4,-20,60,3x^2-x^3)}}}