Question 107590
-3S^2-10S+8 YOU NEED TO FIND 2 FACTORS OF -3 & 2 FACTORS OF 8 THAT WHEN MULTIPLIED & THEN ADDED = -10.
FACTORS OF -3 ARE (1,-3). FACTORS OF 8 ARE (1,8),(-1,-8),(2,4),(-2,-4).
YOU CAN ELIMINATE THE 1&8 BECAUSE 8+3=11, 8-3=5. SO IT MUST BE THE (2,4)   FACTORS. TRY 1*4+-3*2=4-6=-2 NOT A GOOD TRY. 1*2+(-3*4)=2-12=-10 LOOKS LIKE A WINNER.
SO WE HAVE:
(-3S+2)(S+4)
PROOF
-3S+2
S+4 WHEN MULTIPLIED
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-3S^2+2S-12S+8 COMBINING LIKE TERMS WE GET
-3X^2-10S+8