<PRE><B>Question 1160263</B>
Consider a triangle ABC like the one below. Suppose that B= 50 C=72 b=17. (The figure is not drawn to scale.) Solve the triangle.
:
Use the law signs: {{{a/Sin(A) = b/sin(B) = c/sin(C)}}}
find c
{{{c/sin(72) = 17/sin(50)}}}
Cross multiply
sin(50)*c = 17*sin(72)
.766c = 16.168
c = {{{16.168/.766}}}
c = 21.107 is side c
Find A
180 - 50 - 72 = 58 degrees
{{{a/sin(58) = 17/sin(50)}}}
sin(50)*a = sin(58)*17
.766a = 14.417
a = {{{14.417/.766}}}
a = 18.821 is side a
:
We have
A = 58 degrees, a = 18.821
B = 50 degrees, b = 17
C = 72 degrees, c = 21.107
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