Question 1160197


{{{p }}}varies {{{directly}}} with {{{q}}} and {{{inversely}}} with {{{r}}} 

a. the formula connecting {{{p}}}, {{{q}}} ,and {{{r}}}

{{{p=kq/r}}}.... for some constant {{{k}}}

use given: {{{ p =2}}} ,{{{q=10}}},{{{r=25}}} to calculate the constant {{{k}}}

{{{2=k*(10/25)}}}

{{{2/(10/25)=k}}}

{{{1/(5/25)=k}}}

{{{25/5=k}}}

{{{k=5}}}

so, your formula is:

{{{p=5q/r}}}


b.

{{{p}}} when {{{q=6}}} and {{{r =9}}}

{{{p=5(6/9)}}}

{{{p=5(2/3)}}}

{{{p=10/3}}}


c.

{{{q}}} when {{{p =4}}} and {{{r=1/8}}}

{{{4=5q/(1/8)}}}

{{{4(1/8)=5q}}}

{{{(1/2)=5q}}}

{{{q=(1/2)/5}}}

{{{q=1/10}}}