Question 1160192
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Distance equals rate times time.  So the distance John runs is *[tex \Large 10\text{ km/hr}\,\times\,t\text{ hours}]  And the distance Aaron runs is *[tex \Large 12\text{ km/hr}\,\times\,t\text{ hours}]


The distance between them is the hypotenuse of a right triangle where the individual distances are the legs.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  (10t)^2\ +\ (12t)^2\ =\ 80^2]


Simplify and solve the quadratic equation for the positive root.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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