Question 1160169
<pre>
   x     y
  -2     8
   1     2
   2     0
   4    -4
</pre>



Assuming the (x,y) points are on a line, then looking closer at these:
<pre>
  x     y
  -2    8

  0     ?

  1     2
</pre>
Distance d from "?" to 8 ;
{{{d/(0-(-2))=(8-2)/(1-(-2))}}}

{{{d/2=6/3}}}

{{{d/2=2}}}

{{{d=4}}}

The missing y-value is {{{8-d=8-4=4}}};
The y-intercept is  (0,4).