Question 1160152


Find {{{g(-1)}}} and {{{f(g(-1))}}}

{{{f(x)= x^2-x+2}}}
{{{g(x)=4x-3}}}

{{{g(-1)=4(-1)-3}}}

{{{g(-1)=-4-3}}}

{{{g(-1)=-7}}}



{{{f(g(-1))}}}=

first find {{{f(g(x))}}}

{{{f(g(x))=f(g(x))}}}

{{{f(g(x))=f(4x-3)}}}

{{{f(g(x))=(4x-3)^2-(4x-3)+2}}}

{{{f(g(x))=16x^2-24x+9-4x+3+2}}}

{{{f(g(x))=16x^2-28x+14}}}

then

{{{f(g(-1))= 16(-1)^2-28(-1)+14 }}}

{{{f(g(-1))= 16*1+28+14 }}}

{{{f(g(-1))= 58 }}}