Question 1160016


Remember that DOMAIN describes the values that x (or the independent variable) can
be in the problem and RANGE describes the values that y (or the dependent
variable) can be in the problem.

A local youth group is planning a trip to a local amusement park. 
They are taking their church bus which holds {{{32}}} people. 
It will cost ${{{25}}} for parking and tickets to enter the park are ${{{22.50}}} per person. 
The equation that models this situation is: 
{{{c(n) = 22.5n + 25}}} 
where{{{ c}}} represents the {{{cost}}} for the group to go the park and {{{n}}} represents the number of people who go on this excursion. 

In this problem, for the domain, the problem says that the bus can only hold {{{32}}} people,
so I know that my domain has to be less than or equal to {{{32}}}. 
However, since negative numbers are also less than {{{32}}} and I can’t have negative people (my independent variable), I have to have a lower limit on my domain of {{{0}}}.

so, domain is: {{{0<=n<=32}}} 

List the elements: {{{D}}}={{{0}}},{{{1}}},{{{2}}},.....{{{32}}}


To find the range values, I simply use the limits I set on the domain and substitute those
values into my equation to find my limits on the range.
n=0
{{{c(0) = 22.5*0 + 25=25}}} 
{{{c(32) = 22.5*32 + 25=745}}} 

so, the range is: {{{25<=c(n)<=745}}}