Question 1159985

The square of a number increased by 3 times the number is 28. Find the positive number. 

*I think I'm supposed to start with x^2(x squared)+3(x+1)=28, and then turn it into x^2(x squared)+3x+3=28, but I'm not sure of how to continue(or if this is right), so any help is appreciated.

Thanks!
<pre>NO, you're WRONG!
Where did you get 3(x + 1) from? It says "3 times the number." Isn't that 3x, with x being the number?
Therefore, shouldn't the equation be: x<sup>2</sup> + 3x = 28, which then results in: x<sup>2</sup> + 3x - 28 = 0?
Solve that for x and you'll get 2 values for x. Then, give your answer based on this request: "Find the positive number."