Question 1159990
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<pre>

The components of the weight are  


    W*sin(a) = 10*sin(35°) = 10*0.5733 kilograms = 5.733 kilograms = 5.733*9.81 newtons = 56.243 newtons PARALLEL the incline

and

    W*cos(a) = 10*cos(35°) = 10*0.8193 kilograms = 8.193 kilograms = 8.193*9.81 newtons = 80.376 newtons PERPENDICULAR to the incline.
</pre>

Solved.


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Notice that kilograms are not used as the unit of weight (of force) since sixties 
last century, been replaced by Newtons.


    So your source is &nbsp;EXTREMELY &nbsp;outdated.


The numbers by @MowMow are incorrect (!)


Avoid use it (!)


@MowMow, &nbsp;you need seriously update/refresh your knowledge (!) (!)


Had I calculate forces for engineering projects at my positions here in US, &nbsp;as you do in your post, 
I would be fired next day.


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Regarding a diagram, &nbsp;open any textbook in Physics and find a diagram there.


Or look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Vectors/Using-vectors-to-solve-problems-in-Mechanics%3A-Force.lesson>Using vectors to solve problems in Mechanics: Force</A>,  &nbsp;Figures &nbsp;3, &nbsp;4 &nbsp;and &nbsp;5 

in this site.