Question 1159982
For graphically, put both in y=mx+b form and use slope and y-intercept, and make each graph.
{{{system(y=x+5,y=-2x/3+5/3)}}}
{{{graph(400,400,-7,3,-5,5,x+5,-2x/3+5/3)}}}



For "algebraic", you choose how, which steps.

Maybe substitution is what you like?
{{{2x+3(x+5)-5=0}}} and continue from this.
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{{{2x+3x+15=5}}}
{{{5x=-10}}}
{{{x=-2}}}
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{{{y=x+5}}}
{{{y=-2+5}}}
{{{y=3}}}