Question 1159648
The Z value for a 95% confidence interval is 1.960. The standard error is {{{sqrt(65*60/125^3)}}}, which is 0.045 rounded to three decimal places. The true proportion of all U.S. adults in favor of the proposition is 0.52+/-(1.960*0.045),which is 0.520+/-0.088. The lower bound is {{{highlight(0.432)}}} and the upper bound is {{{highlight(0.608)}}}. Click <a href="https://www.sample-size.net/confidence-interval-proportion/">here</a> for a calculator if you have more problems like this.