Question 107530
The best way to handle this one, IMHO, is to start by multiplying through to get rid of all those pesky denominators.


Eq 1) {{{(x/3)+y=3}}} can be written {{{x+3y=9}}} and


Eq 2) {{{(x/2)-(y/4) = 1}}} can be written {{{ 2x-y=4}}}


Next step is to multiply the first equation by -2, resulting in:


Eq 3) {{{-2x-6y=-18}}}


And then add the Eq 2) to Eq 3), term by term giving:


{{{0x-7y=-14}}}


And then solve for y


{{{-7y=-14}}}
{{{7y=14}}}
{{{y=14/7}}}
{{{y=2}}}


{{{ 2x-2=4}}}
{{{2x=6}}}
{{{x=3}}}


Plug your values into both equations and do the arithmetic to check your answer.