Question 1159954

Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 97 km/h  faster than the other. If the two planes are 12,344 kilometers apart after 8 hours, what is the rate of each plane?
<pre>Let slower airplane's speed, be S
Then faster airplane's speed = S + 97
We then get the following DISTANCE equation: 8S + 8(S + 97) = 12,344
8S + 8S + 8(97) = 12,344 
16S = 12,344 - 8(97)
Speed of slower airplane, or {{{highlight_green(matrix(1,6, S, "=", ("12,344" - 8(97))/16, "=", 723, "km/h"))}}}
Now, add 97 to the slower speed to get the faster!