Question 1159757
I think you are asking for the probability distribution of the number of defective converters in the sample.


for 0 it is 50C0*950C3/1000C3=0.8572
alternatively, probability of non defective is (950/1000)(949/999)(948/998)=0.8572

for 1 it is 50C1*950C2/1000C3 or 50 ways to choose the single defective and choose 2 out of 950 is 950C2
probability is 0.1356

for 2 it is 50C2*950C1/1000C3
=0.0070

for 3 it should be the remainder
50C3/1000C3=0.0001
(rounding makes total 0.9999