Question 15905
You need to set up your equation from the problem description as follows:

$x at 8% + $(1000-x) at 10% = $86  Now you solve for x, the amount in the first bank. First change the percents to their decimal equivalents.  8% = 0.08, 10% = 0.1 Now write the algebraic equation.

{{{0.08x + 0.1(1000-x) = 86}}}  Simplify and solve for x.
{{{0.08x + 100 - 0.1x = 86}}}
{{{-0.02x + 100 = 86}}} Subtract 100 from both sides.
{{{-0.02x = -14}}} Divide both sides by -0.02
{{{x = 700}}}

Answer:
$700.00 was deposited in the first bank at 8% interest per annum.
$300.00 was deposited in the second bank at 10% interest per annum.

Check:
0.08($700.00) + 0.1($300.00) = $56.00 + $30.00 = $86.00