Question 1159809
99%CI is mean+/- t*s/sqrt(n)
t(0.995, df=900)=2.581
SE is 0.66/sqrt(901)
half-interval or margin of error is 0.0567
99% CI is (0.963, 1.077) units hours
We are highly confident that the true mean (parameter) is in the given interval. The true mean is unknown and unknowable, but we strongly believe it is in this interval.  (other interpretations as well).