Question 1159830
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With the given roots, a quadratic function has an equation 

    y(x) = a*(x-(-1))*(x-1/4),

where "a" is an arbitrary real number.  Since you want the coefficients from the list, take a = 4 or -4.


You will get then

    y(x) = 4*(x+1)*(x-1/4) = (x+1)*(4x-1) = 4x^2 + 4x - x - 1 = 4x^2 + 3x - 1,

or

    y(x) = -4*(x+1)*(x-1/4) = -(x+1)*(4x-1) = -4x^2 - 4x + x + 1 = -4x^2 - 3x + 1.


These two forms give you two quadratic functions that satisfy the imposed conditions.
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Solved, explained, answered and completed.