Question 1159754

 

Graph {{{f(x) = 3sin(2x) + 2 }}}over the interval [{{{0}}}, {{{2pi}}}]: 


make table:

{{{x}}}|{{{f(x)}}}

{{{0}}}|{{{2}}}...if {{{x=0}}}, {{{f(0) = 3sin(2*0) + 2=2}}}
{{{1}}}|{{{4.7}}}...if {{{x=1}}}, {{{f(1) = 3sin(2*1) + 2=4.7}}}
{{{pi}}}|{{{2}}}...if {{{x=pi}}}, {{{f(pi) = 3sin(2*pi) + 2=2}}}
{{{2.5}}}|{{{-0.9}}}...if {{{x=2.5}}}, {{{f(2.5) = 3sin(2*2.5) + 2=-0.9}}}


{{{drawing ( 600, 600, 0, 6.5, -5, 5,
circle(0,2,.05),circle(1,4.7,.05),circle(pi,2,.05),circle(2.5,-0.9,.05),locate(2pi,0.3,2pi),
line(2pi,-5,2pi,5),
graph( 600, 600, 0, 6.5, -5, 5, 3sin(2x) + 2)) }}}