Question 1159743

Consider the parabola y=x2−6x+4.
What is the axis of symmetry? x=
Compute the coordinates of the vertex: ( 
,	
 )
compute the y-intercept as a point: ( 
,	
 )
find the point symmetric to the y-intercept:
<pre>{{{matrix(1,3, y, "=", x^2 - 6x + 4)}}}
Axis of symmetry: {{{highlight_green(matrix(1,9, x, "=", - b/(2a), "=", - - 6/2(1), "=", 6/2, "=", 3))}}}
y-coordinate of vertex: {{{matrix(1,7, y, "=", 3^2 - 6(3) + 4, "=", 9 - 18 + 4, "=", - 5)}}} 
Coordinates of the vertex: {{{highlight_green(matrix(1,2, "(3,", "- 5)"))}}}
Substitute 0 for x in the equation, and compute to get the y-intercept!