<PRE><B>Question 1159716</B>
The mean is 2260.545
s=281.161
the half-interval is t (0.975, df=10)*s/sqrt(n)
t is 2.228
the half-interval is 2.23*281.16/sqrt(11)
=188.87
add and subtract that from the mean
(2071.7, 2449.4) is the 95% CI of the mean.

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